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Proof step 2 from proof in-vl-append (previous step)

⊦ lref ∈ q + eq-entry(n, lref0) ' ↔ lref = lref0, lref ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ (∃ n0. eq-entry(n0, lref) ∈ q ∨ eq-entry(n0, lref) = eq-entry(n, lref0)) ↔ lref = lref0, ∃ n. eq-entry(n, lref) ∈ q

Rule argument

Additional information

Used simplifier rules: queue-in-vl: ⊦ lref ∈ q ↔ (∃ n. eq-entry(n, lref) ∈ q);%a: ⊦ (q + q0) + q1 = q + q0 + q1; from specification list[erasequeue-base]% ⊦ eqent ∈ eqent0 ' ↔ eqent = eqent0; (s)% ⊦ eqent ∈ q + q0 ↔ eqent ∈ q ∨ eqent ∈ q0; (s)