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Proof step 6 from proof in-vl-append (previous step)

lref = lref0 ⊦ ∃ n. eq-entry(n, lref) ∈ q, ∃ n0. eq-entry(n0, lref) ∈ q ∨ eq-entry(n0, lref) = eq-entry(n, lref0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information