[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 12 from proof in-vl-append0 (previous step)

⊦ (∃ n0. eq-entry(n0, v × m) ∈ q ∨ eq-entry(n0, v × m) = eq-entry(n, lref0)) ↔ (∃ n. eq-entry(n, v × m) ∈ q) ∨ v × m = lref0

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 13:
v × m = lref0 ⊦ (∃ n0. eq-entry(n0, v × m) ∈ q ∨ eq-entry(n0, v × m) = eq-entry(n, lref0)) ↔ (∃ n. eq-entry(n, v × m) ∈ q) ∨ v × m = lref0
Proof step 15:
⊦ (∃ n0. eq-entry(n0, v × m) ∈ q ∨ eq-entry(n0, v × m) = eq-entry(n, lref0)) ↔ (∃ n. eq-entry(n, v × m) ∈ q) ∨ v × m = lref0, v × m = lref0

Rule argument

fma: v × m = lref0

Additional information

Used formulas: v × m = lref0