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Proof step 19 from proof in-vl-in-lebrefs (previous step)

lref ∈ q.lebrefs, eq-entry(n, lref) ∈ q, ∀ lref. lref ∈ q.lebrefs ↔ (∃ n. eq-entry(n, lref) ∈ q) ∧ lref ≠ none ⊦ # q.lebrefs = 0, q.lebrefs = ∅, lref = none, ∃ n. eq-entry(n, lref) = eq-entry(m, none) ∨ eq-entry(n, lref) ∈ q

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 4 terms: n

Additional information

Used terms: n