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Proof step 2 from proof in-vl-subset (previous step)

lref ∈ q1, q1 ⊆ q0 ⊦ lref ∈ q0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
eq-entry(n, lref) ∈ q1, eq-entry(n, lref) ∈ q0, q1 ⊆ q0 ⊦ ∃ n. eq-entry(n, lref) ∈ q0

Rule argument

Additional information

Used simplifier rules: queue-in-vl: ⊦ lref ∈ q ↔ (∃ n. eq-entry(n, lref) ∈ q);%sub-in: ⊦ q ⊆ q0 ∧ eqent ∈ q → eqent ∈ q0; (forward) from specification list-set[erasequeue-base]