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Proof step 5 from proof lebrefs-append-lref (previous step)

∀ n, v, m. (q0 + eq-entry(n, v × m) ').lebrefs = q0.lebrefs ++ (v × m) ⊦ (q0 + eq-entry(n, v × m) ').lebrefs ∪ (lref ≠ none ⊃ ∅ ++ lref;∅) = (q0.lebrefs ∪ (lref ≠ none ⊃ ∅ ++ lref;∅)) ++ (v × m)

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 6:
lref = none, ∀ n, v, m. (q0 + eq-entry(n, v × m) ').lebrefs = q0.lebrefs ++ (v × m) ⊦ (q0 + eq-entry(n, v × m) ').lebrefs ∪ (lref ≠ none ⊃ ∅ ++ lref;∅) = (q0.lebrefs ∪ (lref ≠ none ⊃ ∅ ++ lref;∅)) ++ (v × m)
Proof step 8:
∀ n, v, m. (q0 + eq-entry(n, v × m) ').lebrefs = q0.lebrefs ++ (v × m) ⊦ lref = none, (q0 + eq-entry(n, v × m) ').lebrefs ∪ (lref ≠ none ⊃ ∅ ++ lref;∅) = (q0.lebrefs ∪ (lref ≠ none ⊃ ∅ ++ lref;∅)) ++ (v × m)

Rule argument

fma: lref = none

Additional information

Used formulas: lref = none