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Proof step 9 from proof lebrefs-append-lref (previous step)

∀ n, v, m. (q0 + eq-entry(n, v × m) ').lebrefs = q0.lebrefs ++ (v × m) ⊦ (q0 + eq-entry(n, v × m) ').lebrefs ++ lref = q0.lebrefs ++ lref ++ (v × m), lref = none

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: n, v, m abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ s0 ++ lref ++ lref0 = s0 ++ lref0 ++ lref ↔ true; (s) Used terms: n, v, m