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Proof step 1 from proof lebrefs-none (conclusion)

⊦ eq-entry(n, none) '.lebrefs = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ # eq-entry(n, none) '.lebrefs = 0, eq-entry(n, none) '.lebrefs = ∅

Rule argument

Additional information

Used simplifier rules: size-zero: ⊦ # s0 ≠ 0 → s0 ≠ ∅; (forward) from specification set-basic[lebrefset]%size-zero-01: ⊦ s0 ≠ ∅ → # s0 ≠ 0; (forward) from specification set-basic[lebrefset]