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Proof step 1 from proof rm-v-subseteq (conclusion)

⊦ q - v ⊆ q

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ q ⊆ q0 ↔ (∀ eqent. eqent ∈ q → eqent ∈ q0)
Proof step 3:
⊦ ∀ eqent. eqent ∈ q - v → eqent ∈ q

Rule argument

spec: list-set, inst: erasequeue-base name: subset seq: ⊦ q ⊆ q0 ↔ (∀ eqent. eqent ∈ q → eqent ∈ q0) subst: [q0, q] → [q, q - v] flags: <all paths>

Additional information

Used terms: q, q - v