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Proof step 12 from proof rm-v-subseteq (previous step)

eqent ∈ q0 - v0, ∀ eqent, v. eqent ∈ q0 - v → eqent ∈ q0 ⊦ eqent = eq-entry(m, v0 × m0), eqent ∈ q0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: eqent, v0

Additional information

Used terms: eqent, v0