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Proof step 13 from proof rm-v-subseteq (previous step)

eqent ∈ eq-entry(m, lref) ' + (q0 - v), ∀ eqent, v. eqent ∈ q0 - v → eqent ∈ q0, lref = none ∨ lref.vol ≠ v ⊦ eqent = eq-entry(m, lref), eqent ∈ q0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
eqent ∈ q0 - v, ∀ eqent, v. eqent ∈ q0 - v → eqent ∈ q0, lref = none ∨ lref.vol ≠ v ⊦ eqent = eq-entry(m, lref), eqent ∈ q0

Rule argument

Additional information

Used simplifier rules: a: ⊦ (q + q0) + q1 = q + q0 + q1; from specification list[erasequeue-base]% ⊦ eqent ≠ eqent0 → (eqent ∈ eqent0 ' + q ↔ eqent ∈ q); (s)