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Proof step 2 from proof valid-peb-in-sqnums-h (previous step)

apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar), n0 < n1, valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)), n1 ≤ # apebs ⊦ avhdr.sqn ∈ valid-sqns(v, m, apebs, n1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar), n0 < n1, n0 < # apebs, valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)), n1 ≤ # apebs ⊦ avhdr.sqn ∈ valid-sqns(v, m, apebs, n1)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic