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Proof step 2 from proof valid-peb-in-sqnums (previous step)

apebs[n] = mkpeb(aehdr, avhdr, buf, m0, boolvar), n < # apebs, valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊦ avhdr.sqn ∈ valid-sqns(v, m, apebs)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: valid-sqns: ⊦ valid-sqns(v, m, apebs) = valid-sqns(v, m, apebs, # apebs);%valid-peb-in-sqnums-h: n0 < n1, n1 ≤ # apebs ⊦ valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ∧ apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar) → avhdr.sqn ∈ valid-sqns(v, m, apebs, n1);% ⊦ m ≤ m; (s)