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Proof step 2 from proof valid-peb-sqns-nonempty (previous step)

valid-sqns(v, m, apebs) = ∅, n < # apebs, valid-peb(v, m, apebs[n]) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
valid-sqns(v, m, apebs, # apebs) = ∅, n < # apebs, valid-peb(v, m, apebs[n]) ⊦

Rule argument

Additional information

Used simplifier rules: valid-sqns: ⊦ valid-sqns(v, m, apebs) = valid-sqns(v, m, apebs, # apebs);% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic