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Proof step 1 from proof valid-peb-sqns-nonempty0 (conclusion)

n < # apebs ⊦ apebs[n] = apeb ∧ valid-peb(v, m, apeb) → valid-sqns(v, m, apebs) ≠ ∅

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information