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Proof step 1 from proof valid-sqns-extract-sqn-h (conclusion)

⊦ n < m0 ∧ m0 ≤ # apebs ∧ valid-peb(v, m, apebs[n]) → (∃ bag. valid-sqns(v, m, apebs, m0) = bag ++ apebs[n].vidhdr.sqn)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information