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Proof step 1 from proof valid-sqns-extract-sqn (conclusion)

n < # apebs ⊦ valid-peb(v, m, apebs[n]) → (∃ bag. valid-sqns(v, m, apebs) = bag ++ apebs[n].vidhdr.sqn)

System applied rule normalize

And obtained the following new goals

Proof step 2:
n < # apebs, valid-peb(v, m, apebs[n]) ⊦ ∃ bag. valid-sqns(v, m, apebs) = bag ++ apebs[n].vidhdr.sqn

Rule argument

Additional information