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Proof step 19 from proof valid-sqns-extract2-sqn-h (previous step)

apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar), apebs[n1] = mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0), m1 < # apebs, n0 < # apebs, n1 < # apebs, valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)), valid-peb(v, m, mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0)), n0 ≤ m1, n1 ≤ m1, n1 < m1 ∧ n0 < m1 → valid-sqns(v, m, apebs, m1) = bag ++ avhdr.sqn ++ avhdr0.sqn ⊦ n0 = n1, ∃ bag. valid-sqns(v, m, apebs, m1) ∪ (valid-peb(v, m, apebs[m1]) ⊃ {apebs[m1].vidhdr.sqn} ;∅) = bag ++ avhdr.sqn ++ avhdr0.sqn, n0 < m1 ∧ n1 < m1

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 3

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