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Proof step 29 from proof valid-sqns-extract2-sqn-h (previous step)

apebs[m1] = mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0), apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar), valid-sqns(v, m, apebs, m1) = bag ++ avhdr.sqn, n0 + 1 < # apebs, m1 < # apebs, n0 < # apebs, n0 < m1, valid-peb(v, m, mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0)), valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊦ n0 = m1, ∃ bag. valid-sqns(v, m, apebs, m1) = bag ++ avhdr.sqn

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: bag

Additional information

Used terms: bag