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Proof step 1 from proof valid-sqns-extract2-sqn (conclusion)

⊦ n0 < # apebs ∧ n1 < # apebs ∧ n0 ≠ n1 ∧ valid-peb(v, m, apebs[n0]) ∧ valid-peb(v, m, apebs[n1]) → (∃ bag. valid-sqns(v, m, apebs) = bag ++ apebs[n0].vidhdr.sqn ++ apebs[n1].vidhdr.sqn)

System applied rule normalize

And obtained the following new goals

Proof step 2:
n0 < # apebs, n1 < # apebs, valid-peb(v, m, apebs[n0]), valid-peb(v, m, apebs[n1]) ⊦ n0 = n1, ∃ bag. valid-sqns(v, m, apebs) = bag ++ apebs[n0].vidhdr.sqn ++ apebs[n1].vidhdr.sqn

Proof step 1 from proof valid-sqns-extract2-sqn (conclusion)

System applied rule normalize

And obtained the following new goals

Rule argument

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