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Proof step 7 from proof valid-sqns-nonempty-extract-max (previous step)

avhdr.sqn = valid-sqns(v, m, apebs, # apebs).max, apebs[n] = mkpeb(aehdr, avhdr, buf, m0, boolvar), n < # apebs, valid-peb(v, m, apebs[n]) ⊦ valid-sqns(v, m, apebs, # apebs) = ∅, ∃ n. n < # apebs ∧ valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs, # apebs).max

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
avhdr.sqn = valid-sqns(v, m, apebs, # apebs).max, apebs[n] = mkpeb(aehdr, avhdr, buf, m0, boolvar), n < # apebs, valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊦ valid-sqns(v, m, apebs, # apebs) = ∅, ∃ n. n < # apebs ∧ valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = avhdr.sqn

Proof step 7 from proof valid-sqns-nonempty-extract-max (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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