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Proof step 1 from proof valid-sqns-subarray (conclusion)

n ≤ # apebs ⊦ valid-sqns(v, m, subarray(apebs, 0, n)) = valid-sqns(v, m, apebs, n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n ≤ # apebs ⊦ valid-sqns(v, m, subarray(apebs, 0, n), n) = valid-sqns(v, m, apebs, n)

Rule argument

Additional information

Used simplifier rules: valid-sqns: ⊦ valid-sqns(v, m, apebs) = valid-sqns(v, m, apebs, # apebs);% ⊦ # subarray(apebs, m, n) = n; (s)