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Proof step 1 from proof union-move-left (conclusion)

⊦ ¬ a ∈ st0 ∧ a ∈ st1 ∧ st1[a] = d → st0[a, d] ∪ (st1 -- a) = st0 ∪ st1

System applied rule normalize

And obtained the following new goals

Proof step 2:
st1[a] = d, a ∈ st1 ⊦ st0[a, d] ∪ (st1 -- a) = st0 ∪ st1, a ∈ st0

Rule argument

Additional information