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Proof step 1 from proof abs-erase-emptyq (conclusion)

⊦ v ∈ vols ∧ m < # vols[v] ∧ abs(avols, apebs, vols, q) ∧ vols0 = vols[v, vols[v][m, unmapped]] → abs(avols[v, avols[v][m, erased]], apebs, vols0, [])

System applied rule normalize

And obtained the following new goals

Proof step 2:
vols0 = vols[v, vols[v][m, unmapped]], m < # vols[v], abs(avols, apebs, vols, q), v ∈ vols ⊦ abs(avols[v, avols[v][m, erased]], apebs, vols0, [])

Proof step 1 from proof abs-erase-emptyq (conclusion)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information