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Proof step 27 from proof abs-id-apebs-used (previous step)

# vols[v] = # avols[v], # wlar = # apebs, avols[v][m].data = apebs[vols[v][m].pnum].data, apebs[n, apeb][vols[v][m].pnum] = mkpeb(aehdr, avhdr, buf, m1, boolvar), wlar[n] = wl-entry(m0, stat), avols[v][m].mapped?, m < # avols[v], n < # apebs, valid-ebatbl(apebs, wlar, vols, n0), v ∈ avols, v ∈ vols, apebs[vols[v][m].pnum].fill ≤ avols[v][m].fill, avols[v][m] = erased → ¬ v × m ∈ q ⊦ vols[v][m] = unmapped, stat = used, avols[v][m].data = buf ∧ m1 ≤ avols[v][m].fill

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 28:
# wlar = # apebs, # vols[v] = # avols[v], wlar[n] = wl-entry(m0, stat), apebs[n, apeb][vols[v][m].pnum] = mkpeb(aehdr, avhdr, buf, m1, boolvar), avols[v][m] = mapped(buf0, m2), buf0 = apebs[vols[v][m].pnum].data, avols[v][m].mapped?, n < # apebs, m < # avols[v], valid-ebatbl(apebs, wlar, vols, n0), v ∈ vols, v ∈ avols, apebs[vols[v][m].pnum].fill ≤ m2, avols[v][m] = erased → ¬ v × m ∈ q ⊦ vols[v][m] = unmapped, stat = used, buf0 = buf ∧ m1 ≤ m2

Rule argument

spec: leb name: elim seq: ⊦ leb.mapped? → (buf = leb.data ∧ m = leb.fill ↔ leb = mapped(buf, m)) subst: [leb, buf, m] → [avols[v][m], buf0, m2]

Additional information

Used simplifier rules: ⊦ leb.mapped? → (buf = leb.data ∧ m = leb.fill ↔ leb = mapped(buf, m)); (elim) Used terms: avols[v][m], buf0, m2