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Proof step 1 from proof abs-vols-unmapped (conclusion)

⊦ v ∈ vols ∧ m < # vols[v] ∧ vols[v][m] = unmapped ∧ abs(avols, apebs, vols, q) → ¬ avols[v][m].mapped?

System applied rule normalize

And obtained the following new goals

Proof step 2:
vols[v][m] = unmapped, avols[v][m].mapped?, m < # vols[v], abs(avols, apebs, vols, q), v ∈ vols ⊦

Rule argument

Additional information