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Proof step 19 from proof absexpt-avols-write (previous step)

# vols[v] = # avols[v], apebs[vols[v][m0].pnum] = mkpeb(aehdr, avhdr, buf, m2, boolvar), m0 < # avols[v], m < # avols[v], v ∈ vols, v ∈ avols, ∀ m1. m1 ≠ m ∧ m1 < # avols[v] → (vols[v][m1] = unmapped → ¬ avols[v][m1].mapped?) ∧ ( vols[v][m1] ≠ unmapped → avols[v][m1].mapped? ∧ avols[v][m1].data = apebs[vols[v][m1].pnum].data ∧ apebs[vols[v][m1].pnum].fill ≤ avols[v][m1].fill) ∧ (avols[v][m1] = erased → ¬ v × m1 ∈ q), ∀ v1. (v1 ∈ vols ↔ v1 ∈ avols) ∧ ( v1 ∈ vols → # vols[v1] = # avols[v1] ∧ (∀ m1. (v1 ≠ v ∨ m1 ≠ m) ∧ m1 < # vols[v1] → (vols[v1][m1] = unmapped → ¬ avols[v1][m1].mapped?) ∧ ( vols[v1][m1] ≠ unmapped → avols[v1][m1].mapped? ∧ avols[v1][m1].data = apebs[vols[v1][m1].pnum].data ∧ apebs[vols[v1][m1].pnum].fill ≤ avols[v1][m1].fill) ∧ (avols[v1][m1] = erased → ¬ v1 × m1 ∈ q))) ⊦ m0 = m, (vols[v][m0] = unmapped → ¬ avols[v][m0].mapped?) ∧ (vols[v][m0] ≠ unmapped → avols[v][m0].mapped? ∧ avols[v][m0].data = buf ∧ m2 ≤ avols[v][m0].fill) ∧ (avols[v][m0] = erased → ¬ v × m0 ∈ q)

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: m0

Additional information

Used simplifier rules: ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).data = buf; (s)% ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).fill = m; (s) Used terms: m0