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Proof step 28 from proof absexpt-id-apebs-used (previous step)

# wlar = # apebs, # vols[v0] = # avols[v0], wlar[n] = wl-entry(m0, stat), apebs[n, apeb][vols[v0][m1].pnum] = mkpeb(aehdr, avhdr, buf, m2, boolvar), avols[v0][m1] = mapped(buf0, m3), buf0 = apebs[vols[v0][m1].pnum].data, avols[v0][m1].mapped?, n < # apebs, m1 < # avols[v0], valid-ebatbl(apebs, wlar, vols, n0), v0 ∈ vols, v0 ∈ avols, apebs[vols[v0][m1].pnum].fill ≤ m3, avols[v0][m1] = erased → ¬ v0 × m1 ∈ q, v0 ≠ v ∨ m1 ≠ m ⊦ vols[v0][m1] = unmapped, stat = used, buf0 = buf ∧ m2 ≤ m3

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
# wlar = # apebs, # vols[v0] = # avols[v0], wlar[n] = wl-entry(m0, stat), apebs[n, apeb][vols[v0][m1].pnum] = mkpeb(aehdr, avhdr, buf, m2, boolvar), avols[v0][m1] = mapped(apebs[vols[v0][m1].pnum].data, m3), n < # apebs, m1 < # avols[v0], valid-ebatbl(apebs, wlar, vols, n0), v0 ∈ vols, v0 ∈ avols, apebs[vols[v0][m1].pnum].fill ≤ m3, v0 ≠ v ∨ m1 ≠ m ⊦ vols[v0][m1] = unmapped, stat = used, apebs[vols[v0][m1].pnum].data = buf ∧ m2 ≤ m3

Rule argument

Additional information

Used simplifier rules: ⊦ erased ≠ mapped(buf, m); (s)% ⊦ mapped(buf, m).mapped?; (s)