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Proof step 9 from proof absexpt-idset (previous step)

# vols[v0] = # avols[v0], vols[v][m] = ⌜n⌝ , apebs1[vols[v0][m0].pnum] = mkpeb(aehdr, avhdr, buf, m1, boolvar), avols[v0][m0] = mapped(buf0, m2), buf0 = apebs0[vols[v0][m0].pnum].data, avols[v0][m0].mapped?, m < # vols[v], m0 < # avols[v0], id(apebs1, apebs0, mapped-pebs(vols) -- n), valid-ebatbl(apebs0, wlar, vols, n0), v ∈ vols, v0 ∈ vols, v0 ∈ avols, apebs0[vols[v0][m0].pnum].fill ≤ m2, avols[v0][m0] = erased → ¬ v0 × m0 ∈ q, v0 ≠ v ∨ m0 ≠ m ⊦ vols[v0][m0] = unmapped, buf0 = buf ∧ m1 ≤ m2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
# vols[v0] = # avols[v0], vols[v][m] = ⌜n⌝ , apebs1[vols[v0][m0].pnum] = mkpeb(aehdr, avhdr, buf, m1, boolvar), avols[v0][m0] = mapped(apebs0[vols[v0][m0].pnum].data, m2), m < # vols[v], m0 < # avols[v0], id(apebs1, apebs0, mapped-pebs(vols) -- n), valid-ebatbl(apebs0, wlar, vols, n0), v ∈ vols, v0 ∈ vols, v0 ∈ avols, apebs0[vols[v0][m0].pnum].fill ≤ m2, v0 ≠ v ∨ m0 ≠ m ⊦ vols[v0][m0] = unmapped, apebs0[vols[v0][m0].pnum].data = buf ∧ m1 ≤ m2

Rule argument

Additional information

Used simplifier rules: ⊦ erased ≠ mapped(buf, m); (s)% ⊦ mapped(buf, m).mapped?; (s)