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Proof step 2 from proof absexpt-pebs-write (previous step)

vols[v][m] = ⌜n⌝ , m < # vols[v], valid-ebatbl(apebs, wlar, vols, n0), v ∈ vols ⊦ abs○(avols, apebs[n, apeb], vols, q, v, m) ↔ abs○(avols, apebs, vols, q, v, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
vols[v][m] = ⌜n⌝ , m < # vols[v], valid-ebatbl(apebs, wlar, vols, n0), v ∈ vols ⊦ (∀ v1. (v1 ∈ vols ↔ v1 ∈ avols) ∧ ( v1 ∈ vols → # vols[v1] = # avols[v1] ∧ (∀ m1. (v1 ≠ v ∨ m1 ≠ m) ∧ m1 < # vols[v1] → (vols[v1][m1] = unmapped → ¬ avols[v1][m1].mapped?) ∧ ( vols[v1][m1] ≠ unmapped → avols[v1][m1].mapped? ∧ avols[v1][m1].data = apebs[n, apeb][vols[v1][m1].pnum].data ∧ apebs[n, apeb][vols[v1][m1].pnum].fill ≤ avols[v1][m1].fill) ∧ (avols[v1][m1] = erased → ¬ v1 × m1 ∈ q)))) ↔ (∀ v1. (v1 ∈ vols ↔ v1 ∈ avols) ∧ ( v1 ∈ vols → # vols[v1] = # avols[v1] ∧ (∀ m1. (v1 ≠ v ∨ m1 ≠ m) ∧ m1 < # vols[v1] → (vols[v1][m1] = unmapped → ¬ avols[v1][m1].mapped?) ∧ ( vols[v1][m1] ≠ unmapped → avols[v1][m1].mapped? ∧ avols[v1][m1].data = apebs[vols[v1][m1].pnum].data ∧ apebs[vols[v1][m1].pnum].fill ≤ avols[v1][m1].fill) ∧ (avols[v1][m1] = erased → ¬ v1 × m1 ∈ q))))

Rule argument

Additional information

Used simplifier rules: absexpt-def: ⊦ abs○(avols, apebs, vols, q, v0, m0) ↔ (∀ v. (v ∈ vols ↔ v ∈ avols) ∧ ( v ∈ vols → # vols[v] = # avols[v] ∧ (∀ m. (v ≠ v0 ∨ m ≠ m0) ∧ m < # vols[v] → (vols[v][m] = unmapped → ¬ avols[v][m].mapped?) ∧ ( vols[v][m] ≠ unmapped → avols[v][m].mapped? ∧ avols[v][m].data = apebs[vols[v][m].pnum].data ∧ apebs[vols[v][m].pnum].fill ≤ avols[v][m].fill) ∧ (avols[v][m] = erased → ¬ v × m ∈ q))));% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic