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Proof step 13 from proof absexpt-v-vols-write (previous step)

# evol = # ebatbl, ∀ v0. (v0 ∈ vols ↔ v0 ∈ avols) ∧ ( v0 ∈ vols → # vols[v0] = # avols[v0] ∧ (∀ m. m < # vols[v0] → (vols[v0][m] = unmapped → ¬ avols[v0][m].mapped?) ∧ ( vols[v0][m] ≠ unmapped → avols[v0][m].mapped? ∧ avols[v0][m].data = apebs[vols[v0][m].pnum].data ∧ apebs[vols[v0][m].pnum].fill ≤ avols[v0][m].fill) ∧ (avols[v0][m] = erased → ¬ v0 × m ∈ q))) ⊦ v ∈ avols, v ∈ vols, ∀ v0. (v0 ∈ vols[v, ebatbl] ↔ v0 ∈ avols[v, evol]) ∧ ( v0 ∈ vols[v, ebatbl] → # vols[v, ebatbl][v0] = # avols[v, evol][v0] ∧ ( v0 ≠ v → (∀ m. m < # vols[v0] → (vols[v0][m] = unmapped → ¬ avols[v0][m].mapped?) ∧ ( vols[v0][m] ≠ unmapped → avols[v0][m].mapped? ∧ avols[v0][m].data = apebs[vols[v0][m].pnum].data ∧ apebs[vols[v0][m].pnum].fill ≤ avols[v0][m].fill) ∧ (avols[v0][m] = erased → ¬ v0 × m ∈ q))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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