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Proof step 3 from proof absf-size (previous step)

m ≤ # ebatbl ⊦ # absf(v, evol, apebs, ebatbl, q, m) = # ebatbl

User applied rule structural induction

And obtained the following new goals

Proof step 4:
m0 +1 ≤ # ebatbl, ∀ ebatbl, v, evol, apebs, q. m0 ≤ # ebatbl → # absf(v, evol, apebs, ebatbl, q, m0) = # ebatbl ⊦ # absf(v, evol, apebs, ebatbl, q, m0 +1) = # ebatbl

Rule argument

indvar: m

Additional information

Used simplifier rules: absf-base: ⊦ absf(v, evol, apebs, ebatbl, q, 0) = mkabstractvolume(# ebatbl);%nat freely generated by 0, +1;;% ⊦ # mkabstractvolume(n) = n; (s)