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Proof step 5 from proof inv-create-volume (previous step)

# apebs = # wlar, apebs0 = apebs, q0 = q, vols0 = vols, vtblpnum0 = vtblpnum, vtblpnum1 = EB_PAGE_SIZE, vtblpnum2 = LEB_SIZE, bflipset-cons(bflipset, wlar), ubi-io-inv(apebs), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar), v ∈ vols ∨ v = VTBL_VOLID ⊦ ⟪err := EINVAL⟫ ( # apebs = # wlar ∧ unique-sqns(apebs) ∧ valid-global-sqn(apebs, sqnum) ∧ valid-wl(apebs, wlar) ∧ valid-eraseq(q) ∧ valid-eraseq(wlar, q) ∧ valid-eraseq(apebs, q) ∧ ¬ VTBL_VOLID ∈ vols ∧ bflipset-cons(bflipset, wlar) ∧ valid-ebatbl(apebs, wlar, vols, vtblpnum0) ∧ valid-vtbl(apebs, vols, wlar, vtblpnum0) ∧ ubi-io-inv(apebs) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ id(apebs, apebs0, mapped-pebs(vols)) ∧ (err = ESUCCESS → ¬ v ∈ vols0 ∧ vols = vols0[v, fill(mkebatbl(n), unmapped)] ∧ q.lebrefs ⊆ ∅ ++ (VTBL_VOLID × VTBL_LNUM)) ∧ (err ≠ ESUCCESS → q.lebrefs ⊆ q0.lebrefs ∧ vols = vols0)), vtblpnum ∈ q, VTBL_VOLID ∈ vols

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ ESUCCESS ≠ EINVAL; (s)% ⊦ ⌊EINVAL⌋ ; (s)% ⊦ id(apebs, apebs, ns); (s)% ⊦ s0 ⊆ s0; (s)