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Proof step 137 from proof inv-format (previous step)

# apebs0 = n0 + vtblpnum0, # wlar = n0 + vtblpnum0, apebs0[vtblpnum2] = mkpeb(aehdr0, avhdr, buf, m, boolvar), err = err0, err = ESUCCESS, err1 = err, n = # apebs0, vtblpnum = vtblpnum0, apebs0[vtblpnum0].bad, vtblpnum < # wlar, vtblpnum0 < # apebs0, ubi-io-initial(apebs0), vtblpnum2 ≤ n0 + vtblpnum0, vtblpnum2 ≠ n0 + vtblpnum0 → ¬ boolvar, ∀ n3. n3 < vtblpnum0 → (apebs0[n3].bad → wlar[n3] = wl-entry(0, erroneous)) ∧ (¬ apebs0[n3].bad → apebs0[n3].echdr.valid? ∧ wlar[n3] = wl-entry(apebs0[n3].echdr.ec, free) ∧ apebs0[n3].vidhdr = empty), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪vtblpnum0 := vtblpnum + 1⟫ ( vtblpnum0 ≤ # apebs0 ∧ n = # apebs0 ∧ # wlar[vtblpnum, wl-entry(0, erroneous)] = # apebs0 ∧ (err1 = ESUCCESS ∨ ⌊err1⌋ ) ∧ ( err1 = ESUCCESS → vtblpnum2 ≤ # apebs0 ∧ (∀ n3. n3 < vtblpnum0 → (apebs0[n3].bad → wlar[vtblpnum, wl-entry(0, erroneous)][n3] = wl-entry(0, erroneous)) ∧ ( ¬ apebs0[n3].bad → apebs0[n3].echdr.valid? ∧ wlar[vtblpnum, wl-entry(0, erroneous)][n3] = wl-entry(apebs0[n3].echdr.ec, free) ∧ apebs0[n3].vidhdr = empty)) ∧ (vtblpnum2 ≠ # apebs0 → ¬ apebs0[vtblpnum2].bad)) ∧ # apebs0 < n0 + vtblpnum0), n0 = 0

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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