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Proof step 30 from proof inv-read (previous step)

# buf1 = # buf, # apebs = # wlar, apebs[m] = mkpeb(aehdr, avhdr, buf0, m1, false), vols[v][vtblpnum4] = ⌜m⌝ , wlar[m] = wl-entry(m0, used), err = err0, vtblpnum4 < # vols[v], m < # wlar, bflipset-cons(bflipset, wlar), range=(buf1, 0, buf, 0, n0), range=(buf1, n0 + n, buf, n0 + n, # buf - n0 + n), ubi-io-inv(apebs), ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf0, m1, false)), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum5), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-peb(v, vtblpnum4, mkpeb(aehdr, avhdr, buf0, m1, false)), valid-peb(mkpeb(aehdr, avhdr, buf0, m1, false)), valid-vtbl(apebs, vols, wlar, vtblpnum5), valid-wl(apebs, wlar), v ∈ vols, vtblpnum3 + n ≤ LEB_SIZE, n0 + n ≤ # buf, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪buf := buf1; if err = ESUCCESS ∧ bitflips then bflipset := bflipset ++ m⟫ bflipset-cons(bflipset, wlar), err = ESUCCESS, m = vtblpnum5, VTBL_VOLID ∈ vols, vtblpnum5 ∈ q, m ∈ q

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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