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Proof step 34 from proof inv-read (previous step)

# apebs = # wlar, wlar[m] = wl-entry(m0, used), vols[v][vtblpnum4] = ⌜m⌝ , apebs[m] = mkpeb(aehdr, avhdr, buf0, m1, false), m < # wlar, vtblpnum4 < # vols[v], bflipset-cons(bflipset, wlar), ubi-io-inv(apebs), ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf0, m1, false)), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum5), valid-eraseq(apebs, q), valid-eraseq(wlar, q), valid-eraseq(q), valid-global-sqn(apebs, sqnum), valid-peb(mkpeb(aehdr, avhdr, buf0, m1, false)), valid-peb(v, vtblpnum4, mkpeb(aehdr, avhdr, buf0, m1, false)), valid-vtbl(apebs, vols, wlar, vtblpnum5), valid-wl(apebs, wlar), v ∈ vols, n0 + n ≤ # buf, vtblpnum3 + n ≤ LEB_SIZE, ⌊err0⌋ ⊦ m = vtblpnum5, m ∈ q, vtblpnum5 ∈ q, VTBL_VOLID ∈ vols, ∃ buf1. # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, # buf - n0 + n)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 35:
# apebs = # wlar, # buf = n1 + n0 + n, apebs[m] = mkpeb(aehdr, avhdr, buf0, m1, false), vols[v][vtblpnum4] = ⌜m⌝ , wlar[m] = wl-entry(m0, used), vtblpnum4 < # vols[v], m < # wlar, bflipset-cons(bflipset, wlar), ubi-io-inv(apebs), ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf0, m1, false)), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum5), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-peb(v, vtblpnum4, mkpeb(aehdr, avhdr, buf0, m1, false)), valid-peb(mkpeb(aehdr, avhdr, buf0, m1, false)), valid-vtbl(apebs, vols, wlar, vtblpnum5), valid-wl(apebs, wlar), v ∈ vols, vtblpnum3 + n ≤ LEB_SIZE, n0 + n ≤ # buf, ⌊err0⌋ ⊦ m = vtblpnum5, VTBL_VOLID ∈ vols, vtblpnum5 ∈ q, m ∈ q, ∃ buf1. # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, n1)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [# buf, n0 + n, n1]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: # buf, n0 + n, n1