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Proof step 245 from proof inv-recover (previous step)

# wlar1 = # wlar, # apebs0 = # wlar, apebs0[vtblpnum1] = mkpeb(aehdr, avhdr, buf1, m0, false), recs0[VTBL_VOLID × VTBL_LNUM] = recovery-entry(vtblpnum1, avhdr.sqn), buf = mkbuf(LEB_SIZE), err = err0, n = LEB_SIZE, n0 = 0, vtblpnum = 0, vtblpnum0 = vtblpnum1, vtblpnum1 < # wlar, nx < # wlar, bflipset-cons(bflipset, wlar), bflipset-cons(bflipset1, wlar1), indices-erasing(wlar, nx), ubi-io-inv(apebs0), ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf1, m0, false)), unique-sqns(apebs0), valid-ebatbl(apebs0, wlar1, vols1, vtblpnum1), valid-eraseq(wlar, q), valid-eraseq(apebs0, q1), valid-eraseq(wlar1, q1), valid-eraseq(q1), valid-eraseq-stronger(apebs0, q), valid-global-sqn(apebs0, sqnum), valid-global-sqn(apebs0, vtblpnum5), valid-recs(apebs0, wlar, recs0), valid-recs-sqns(apebs0, recs0), valid-vtbl(apebs0, vols1, wlar1, vtblpnum1), valid-wl(apebs0, wlar), valid-wl(apebs0, wlar1), VTBL_VOLID × VTBL_LNUM ∈ recs0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ err = ESUCCESS, dups(nx), vtblpnum1 ∈ q1, VTBL_VOLID ∈ vols1, vtblpnum1 ∈ q, ∀ buf1. # buf1 = # buf → range=(buf1, 0, buf, 0, n0) → # buf ≥ n0 + n

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ n < n; (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ n ≥ m ↔ m ≤ n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)% ⊦ 0 ≤ m; (s)% ⊦ range=(buf, n0, buf0, n1, 0) ↔ n0 ≤ # buf ∧ n1 ≤ # buf0; (s)% ⊦ # mkbuf(n) = n; (s)