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Proof step 88 from proof inv-recover (previous step)

# wlar1 = # wlar, # apebs0 = # wlar, apebs0[m] = mkpeb(aehdr, avhdr, buf1, m0, false), recs0[VTBL_VOLID × VTBL_LNUM] = recovery-entry(m, avhdr.sqn), m < # wlar, nx < # wlar, bflipset-cons(bflipset, wlar), bflipset-cons(bflipset1, wlar1), bflipset-cons(bflipset0, wlar), indices-erasing(wlar, nx), ubi-io-inv(apebs0), ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf1, m0, false)), unique-sqns(apebs0), unmapped-vols(vols0), valid-ebatbl(apebs0, wlar1, vols1, m), valid-eraseq(wlar, q), valid-eraseq(apebs0, q1), valid-eraseq(wlar1, q1), valid-eraseq(q1), valid-eraseq-stronger(apebs0, q), valid-global-sqn(apebs0, sqnum), valid-global-sqn(apebs0, vtblpnum5), valid-recs(apebs0, wlar, recs0), valid-recs-sqns(apebs0, recs0), valid-vtbl(apebs0, vols0, wlar, m), valid-vtbl(apebs0, vols1, wlar1, m), valid-vtbl-weak(apebs0, m), valid-wl(apebs0, wlar), valid-wl(apebs0, wlar1), VTBL_VOLID × VTBL_LNUM ∈ recs0, ¬ dups(nx), ¬ VTBL_VOLID ∈ vols1, ¬ m ∈ q1, ¬ m ∈ q, ¬ VTBL_VOLID ∈ vols0 ⊦ ⟪recs := recs0; ubi_init_vols_mappings#(m, apebs0; recs0, vols0, wlar, q, bflipset0); let n = 0 in ubi_fix_ecs#(n; nx, wlar)⟫ ( # wlar1 = # wlar ∧ valid-wl(apebs0, wlar) ∧ valid-eraseq(q) ∧ valid-eraseq(wlar, q) ∧ valid-eraseq(apebs0, q) ∧ ¬ VTBL_VOLID ∈ vols0 ∧ bflipset-cons(bflipset0, wlar) ∧ valid-ebatbl(apebs0, wlar, vols0, recs[VTBL_VOLID × VTBL_LNUM].pnum) ∧ valid-vtbl(apebs0, vols0, wlar, recs[VTBL_VOLID × VTBL_LNUM].pnum) ∧ is-max(apebs0, vols0, wlar, q, bflipset0, recs[VTBL_VOLID × VTBL_LNUM].pnum, sqnum) ∧ q.lebrefs ⊆ q1.lebrefs ∧ vols1 ⊆ vols0 ∧ vols0⌈vols1, q1⌉)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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