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Proof step 67 from proof inv-wl-worker (previous step)

# apebs = # wlar, avhdr.sqn = valid-sqns(v, m, apebs).max, apebs[vtblpnum2] = mkpeb(aechdr(m1), avhdr, buf, m3, false), apebs[vtblpnum1] = mkpeb(aehdr, empty, mkempbuf(LEB_SIZE), 0, false), wlar[vtblpnum2] = wl-entry(m1, used), wlar[vtblpnum1] = wl-entry(m0, free), aehdr.valid?, vtblpnum2 < # wlar, vtblpnum1 < # wlar, bflipset-cons(bflipset, wlar), bflipset-cons(bflipset0, wlar), ubi-io-inv(apebs), ubi-io-peb-inv(mkpeb(aechdr(m1), avhdr, buf, m3, false)), unique-sqns(apebs), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-peb(mkpeb(aechdr(m1), avhdr, buf, m3, false)), valid-peb(v, m, mkpeb(aechdr(m1), avhdr, buf, m3, false)), valid-vtbl(apebs, vols, wlar, vtblpnum4), bflipset = ∅ → m1 + WL_THRESHOLD ≤ m0, ∀ v, m, n. vols[v][m] = ⌜n⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n].status = used ∧ n < # apebs ∧ n < # wlar ∧ apebs[n].vidhdr.valid? ∧ apebs[n].vidhdr.vol = v ∧ apebs[n].vidhdr.leb = m ∧ n ≠ vtblpnum4 ⊦ vtblpnum4 = vtblpnum1, VTBL_VOLID ∈ vols, vtblpnum4 ∈ q, vtblpnum2 ∈ q, v ∈ vols ∧ m < # vols[v], v = VTBL_VOLID ∧ m = VTBL_LNUM

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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