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Proof step 2 from proof lf-valid-eraseq-stronger-notin-recs (previous step)

# apebs = # wlar, valid-eraseq(wlar, q), valid-eraseq-stronger(apebs, q), valid-recs(apebs, wlar, recs), valid-wl(apebs, wlar) ⊦ valid-sqns(v, m, apebs) = ∅, v × m ∈ recs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# apebs = # wlar, valid-eraseq(wlar, q), valid-eraseq-stronger(apebs, q), valid-recs(apebs, wlar, recs), valid-wl(apebs, wlar) ⊦ valid-sqns(v, m, apebs) = ∅, v × m ∈ recs

Proof step 2 from proof lf-valid-eraseq-stronger-notin-recs (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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