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Proof step 6 from proof lf-valid-recs-in-apebs (previous step)

recs[v × m] = recovery-entry(n0, n1), v × m ∈ recs, m0 ≤ # apebs, m0 ≤ n0, ∀ ladr, m1. ladr ∈ recs ∧ recs[ladr].pnum = m1 ↔ wlar[m1].status = used ∧ m1 < m0 ∧ apebs[m1].vidhdr.vol = ladr.vol ∧ apebs[m1].vidhdr.leb = ladr.leb ⊦

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: v × m, n0

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); (s)% ⊦ recovery-entry(m, m0).pnum = m; (s) Used terms: v × m, n0