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Proof step 14 from proof lf-valid-recs-notin-eraseq (previous step)

apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar), recs[avhdr.vol × avhdr.leb] = recovery-entry(n0, n1), wlar[n0] = wl-entry(m1, used), n0 < # apebs, valid-eraseq(wlar, q), avhdr.vol × avhdr.leb ∈ recs, n0 ∈ q, ∀ ladr, m. ladr ∈ recs ∧ recs[ladr].pnum = m ↔ wlar[m].status = used ∧ m < # apebs ∧ apebs[m].vidhdr.vol = ladr.vol ∧ apebs[m].vidhdr.leb = ladr.leb ⊦ n0 = # apebs

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 8 terms: avhdr.vol × avhdr.leb, n0

Additional information

Used simplifier rules: ⊦ n ∈ q ∧ valid-eraseq(wlar, q) ∧ wlar[n] = wl-entry(m, stat) → wlar[n] = wl-entry(m, erasing); (s)% ⊦ wl-entry(m, stat).status = stat; (s)% ⊦ used ≠ erasing; (s)% ⊦ recovery-entry(m, m0).pnum = m; (s) Used terms: avhdr.vol × avhdr.leb, n0