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Proof step 2 from proof lf-valid-recs-notin-eraseq (previous step)

recs[v × m] = recovery-entry(n0, n1), valid-eraseq(wlar, q), valid-recs(apebs, wlar, recs), n0 ∈ q, v × m ∈ recs ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information