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Proof step 7 from proof lf-valid-recs-notin-eraseq (previous step)

recs[v × m] = recovery-entry(n0, n1), valid-eraseq(wlar, q), v × m ∈ recs, n0 ∈ q, ∀ ladr, m. ladr ∈ recs ∧ recs[ladr].pnum = m ↔ wlar[m].status = used ∧ m < # apebs ∧ apebs[m].vidhdr.vol = ladr.vol ∧ apebs[m].vidhdr.leb = ladr.leb ⊦ n0 = # apebs

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 8:
v × m ∈ recs ∧ recs[v × m].pnum = n0 ↔ wlar[n0].status = used ∧ n0 < # apebs ∧ apebs[n0].vidhdr.vol = (v × m).vol ∧ apebs[n0].vidhdr.leb = (v × m).leb, recs[v × m] = recovery-entry(n0, n1), valid-eraseq(wlar, q), n0 ∈ q, v × m ∈ recs, ∀ ladr, m. ladr ∈ recs ∧ recs[ladr].pnum = m ↔ wlar[m].status = used ∧ m < # apebs ∧ apebs[m].vidhdr.vol = ladr.vol ∧ apebs[m].vidhdr.leb = ladr.leb ⊦ n0 = # apebs

Rule argument

pos: left 5 terms: v × m, n0

Additional information

Used terms: v × m, n0