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Proof step 5 from proof lf-valid-recs-sqns-vidhdr (
previous step
)
⊦ valid-recs-sqns(apebs, recs) ↔ (∀ ladr. ladr ∈ recs → recs[ladr].pnum < # apebs ∧ apebs[recs[ladr].pnum].vidhdr.sqn = recs[ladr].sqn)
A spec-lemma