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Proof step 6 from proof lf-valid-recs-valid-peb (previous step)

# apebs = # wlar, recs[v × m] = recovery-entry(n0, n1), n0 < m0, n0 < # wlar, valid-wl(subarray(apebs, 0, m0), subarray(wlar, 0, m0)), v × m ∈ recs, m0 ≤ # wlar, ∀ ladr, m1. ladr ∈ recs ∧ recs[ladr].pnum = m1 ↔ wlar[m1].status = used ∧ m1 < m0 ∧ apebs[m1].vidhdr.vol = ladr.vol ∧ apebs[m1].vidhdr.leb = ladr.leb ⊦ valid-peb(v, m, apebs[n0])

User applied rule all left

And obtained the following new goals

Proof step 7:
# apebs = # wlar, v × m ∈ recs ∧ recs[v × m].pnum = n0 ↔ wlar[n0].status = used ∧ n0 < m0 ∧ apebs[n0].vidhdr.vol = (v × m).vol ∧ apebs[n0].vidhdr.leb = (v × m).leb, recs[v × m] = recovery-entry(n0, n1), n0 < # wlar, n0 < m0, valid-wl(subarray(apebs, 0, m0), subarray(wlar, 0, m0)), v × m ∈ recs, m0 ≤ # wlar ⊦ valid-peb(v, m, apebs[n0])

Rule argument

pos: left 8 terms: v × m, n0 abort: F discard: T computed: T

Additional information

Used terms: v × m, n0