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Proof step 1 from proof ls-datasize-empbuf-append-lower (conclusion)

⊦ datasize(mkempbuf(n) + buf, n) = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls-datasize-zero: n ≤ # buf ⊦ datasize(buf, n) = 0 ↔ (∃ buf0. buf = mkempbuf(n) + buf0);% ⊦ buf + buf0 = buf + buf1 ↔ buf0 = buf1; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ ¬ m + n < m; (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ # mkempbuf(n) = n; (s)% ⊦ #(buf + buf0) = # buf + # buf0; (s)