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Proof step 15 from proof ls-datasize-zero (previous step)

# buf = n1 + n, n0 < n1 + n, n0 < # mkempbuf(n) + # subarray(buf, n, n1), n ≤ n0, # mkempbuf(n) ≤ n0, ∀ n0. n0 < n → buf[n0] = empty ⊦ buf[n0] = subarray(buf, n, n1)[n0 - # mkempbuf(n)], n1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
# buf = n1 + n, n0 < n1 + n, n0 < n + n1, n ≤ n0, ∀ n0. n0 < n → buf[n0] = empty ⊦ buf[n0] = subarray(buf, n, n1)[n0 - n], n1 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ # subarray(buf, m, n) = n; (s)% ⊦ # mkempbuf(n) = n; (s)