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Proof step 17 from proof ls-datasize-zero (previous step)

# buf = n1 + n, n0 < n1 + n, n0 < # mkempbuf(n), ∀ n0. n0 < n → buf[n0] = empty ⊦ buf[n0] = mkempbuf(n)[n0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
# buf = n1 + n, n0 < n, n0 < n1 + n, ∀ n0. n0 < n → buf[n0] = empty ⊦ buf[n0] = empty

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → mkempbuf(n)[m] = empty; (s)% ⊦ # mkempbuf(n) = n; (s)