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Proof step 6 from proof ls-datasize-zero (previous step)

# buf = n1 + n, n ≤ # buf, ∀ n0. n0 < n → buf[n0] = empty ⊦ buf = mkempbuf(n) + subarray(buf, n, n1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# buf = n1 + n, ∀ n0. n0 < n → buf[n0] = empty ⊦ buf = mkempbuf(n) + subarray(buf, n, n1)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)